12t=(99t)^2

Solution for 12t=(99t)^2 equation:

12t=(99t)^2

We move all terms to the left:

12t-((99t)^2)=0

determiningTheFunctionDomain
12t-99t^2=0

We add all the numbers together, and all the variables

-99t^2+12t=0

a = -99; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-99)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-99}=\frac{-24}{-198}
=4/33
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-99}=\frac{0}{-198}
=0
$